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4x^2-184x-252=0
a = 4; b = -184; c = -252;
Δ = b2-4ac
Δ = -1842-4·4·(-252)
Δ = 37888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{37888}=\sqrt{1024*37}=\sqrt{1024}*\sqrt{37}=32\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-184)-32\sqrt{37}}{2*4}=\frac{184-32\sqrt{37}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-184)+32\sqrt{37}}{2*4}=\frac{184+32\sqrt{37}}{8} $
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